### Puzzle:

You have three types of biscuits:

**Round biscuit**(RB)**Square biscuit**(SB)**Triangle biscuit**(TB)

**જવાબ** 👇👇👇👇👇👇

Each type of biscuit has a certain value. You need to determine the value of each biscuit based on the equations provided in the puzzle image.

### Example Puzzle with Solution:

**RB + RB + RB = 30****RB + SB + SB = 20****SB + TB + TB = 9****TB + TB + TB = 3**

### Solution:

- From equation 4:
**TB + TB + TB = 3**, we can deduce: TB=1TB=1 - Substituting
**TB**value into equation 3:**SB + TB + TB = 9**: SB+1+1=9SB+1+1=9 SB+2=9SB+2=9 SB=7SB=7 - Substituting
**SB**value into equation 2:**RB + SB + SB = 20**: RB+7+7=20RB+7+7=20 RB+14=20RB+14=20 RB=6RB=6

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### Values:

**Round biscuit (RB) = 6****Square biscuit (SB) = 7****Triangle biscuit (TB) = 1**

start 5+5+5=15

10+10×8=90

4×4+7=23

8+5×14=78 to note the points

👉 – for second one 10 comes from 5+5 bcz there r 2 of them stacked. – and most importantly the answer u get for second one is 8 but don’t forget to half it as there r 2 of them so the value is 4 for one piece -the cheese 🧀carries 7 as value add another u get 14 yeah then that’s all –

**જવાબ** 👇👇👇👇👇👇

**જવાબ છે 78**

This example demonstrates how to solve a typical biscuit picture puzzle using algebraic methods. If you have a specific image or puzzle you’d like help with, please share the details, and I can provide a step-by-step solution for that puzzle.